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    How often will a double flop be the same rank
  
        
  
    
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  | package main | |
| import ( | |
| "fmt" | |
| "math/rand" | |
| "sort" | |
| "time" | |
| ) | |
| func createDeck() *[52]int { | |
| var deck [52]int | |
| for i := 0; i < 52; i++ { | |
| deck[i] = i | |
| } | |
| return &deck | |
| } | |
| func shuffleDeck(a *[52]int) { | |
| rand.Seed(time.Now().UnixNano()) | |
| rand.Shuffle(len(a), func(i, j int) { a[i], a[j] = a[j], a[i] }) | |
| } | |
| /* | |
| For these purposes, we will rank A as 1, 2 as 2, ... K as 13. | |
| */ | |
| func getRankOfFlop(flop []int) []int { | |
| // var flopRank []int | |
| flopRank := make([]int, 3) | |
| for i, card := range flop { | |
| // Adding 1 so we go from 1-13 instead of 0-12. | |
| flopRank[i] = (card % 13) + 1 | |
| } | |
| return flopRank | |
| } | |
| func main() { | |
| numOfRuns := 10000000 | |
| deck := createDeck() | |
| numOfMatchingFlops := 0 | |
| for i := 0; i < numOfRuns; i++ { | |
| shuffleDeck(deck) | |
| // First three cards | |
| firstFlop := deck[0:3] | |
| secondFlop := deck[3:6] | |
| firstFlopRank := getRankOfFlop(firstFlop) | |
| secondFlopRank := getRankOfFlop(secondFlop) | |
| sort.Ints(firstFlopRank) | |
| sort.Ints(secondFlopRank) | |
| matchingFlop := true | |
| for j := 0; j < 3; j++ { | |
| if firstFlopRank[j] != secondFlopRank[j] { | |
| matchingFlop = false | |
| break | |
| } | |
| } | |
| if matchingFlop { | |
| numOfMatchingFlops += 1 | |
| } | |
| } | |
| fmt.Println("Number of matching flops: ", numOfMatchingFlops) | |
| fmt.Println("Percentage: ", fmt.Sprintf("%.2f", float64(numOfMatchingFlops)/float64(numOfRuns)*100), "%") | |
| } | 
  
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