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January 22, 2017 12:28
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Animation to show how a distance of a point to a line segment looks. Ref: http://stackoverflow.com/a/1501725
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PVector lineStart, lineEnd, point; | |
void setup() { | |
size(600, 600); | |
updatePoints(); | |
} | |
void draw() { | |
background(0); | |
float d = distToSegment(lineStart, lineEnd, point); | |
stroke(255); | |
noFill(); | |
line(lineStart.x, lineStart.y, lineEnd.x, lineEnd.y); | |
point(point.x, point.y); | |
ellipse(point.x, point.y, d * 2, d * 2); | |
updatePoints(); | |
} | |
void updatePoints() { | |
float r = frameCount / 30.0; | |
lineStart = new PVector(cos(r), sin(r)); | |
lineStart.mult(width / 10.0); | |
lineStart.add(100, 100); | |
lineEnd = new PVector(cos(r + HALF_PI), sin(r * 1.1 + HALF_PI)); | |
lineEnd.mult(40); | |
lineEnd.add(500, 500); | |
if(mouseX == 0 && mouseY == 0) { | |
float r2 = frameCount / 40.0; | |
point = new PVector(cos(r2), sin(r2)); | |
point.mult(width / 2.0); | |
point.add(width / 2.0, height / 2.0); | |
} | |
else { | |
point = new PVector(mouseX, mouseY); | |
} | |
} | |
float dist_squared(PVector a, PVector b) { | |
return (a.x - b.x) * (a.x - b.x) + (a.y - b.y) * (a.y - b.y); | |
} | |
float distToSegment(PVector v, PVector w, PVector p) { | |
float l2 = dist_squared(v, w); | |
if(l2 == 0.0) { | |
return PVector.dist(p, v); | |
} | |
float t = max(0, min(1, PVector.dot(p.copy().sub(v), w.copy().sub(v)) / l2)); | |
PVector projection = v.copy().add(w.copy().sub(v).mult(t)); | |
return PVector.dist(p, projection); | |
} |
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