[2015-11-02] Challenge #239 [Easy] A Game of Threes

/*
https://goo.gl/z0Rk3j
Written in JavaScript

Background

Back in middle school, I had a peculiar way of dealing with super boring classes. I would take my handy pocket calculator and play a "Game of Threes". Here's how you play it:
First, you mash in a random large number to start with. Then, repeatedly do the following:
If the number is divisible by 3, divide it by 3.
If it's not, either add 1 or subtract 1 (to make it divisible by 3), then divide it by 3.
The game stops when you reach "1".
While the game was originally a race against myself in order to hone quick math reflexes, it also poses an opportunity for some interesting programming challenges. Today, the challenge is to create a program that "plays" the Game of Threes.
Challenge Description

The input is a single number: the number at which the game starts. Write a program that plays the Threes game, and outputs a valid sequence of steps you need to take to get to 1. Each step should be output as the number you start at, followed by either -1 or 1 (if you are adding/subtracting 1 before dividing), or 0 (if you are just dividing). The last line should simply be 1.
Input Description

The input is a single number: the number at which the game starts.
100
Output Description

The output is a list of valid steps that must be taken to play the game. Each step is represented by the number you start at, followed by either -1 or 1 (if you are adding/subtracting 1 before dividing), or 0 (if you are just dividing). The last line should simply be 1.
100 -1
33 0
11 1
4 -1
1
Challenge Input

31337357

*/

var x = 31337357;

// var x = prompt("Pick a number, any number!");

var GameofThrees = function(x) {
// Create a function to hold everything
	while (x != 1) {
// Create a while loop to keep running the function until the number is 1
		if (x % 3 === 0){
			console.log(x + " 0");
			x/=3
// If the function is evenly divisible by 3, divide and reassign
		} else if (((x + 1)/3) % 1 === 0){
				console.log(x + " 1");
				x ++;
// Otherwise, if adding 1 makes it evenly divisible by 3, do that
		} else {
				console.log(x + " -1");
				x--;
// Otherwise, subtract 1 and repeat until it equals 1
		}
	}
	console.log(x);
// Print out the final "1"
};

GameofThrees(x);