Age in years and Day

.c

//Program to find the age in days.
#include<stdio.h>
#include<process.h>
int main()
{
    system("cls");
    int m[12]={31,28,31,30,31,30,31,31,30,31,30,31};
    int d1,d2,m1,m2,y1,y2,c1,c2=0,c3=0,c4=0,c5=0,k=0;
    printf("Enter Current Date in dd-mm-yy fromat:");           
    scanf("%d/%d/%d",&d1,&m1,&y1);
    printf("Enter Birth Date in dd-mm-yy fromat:");           
    scanf("%d/%d/%d",&d2,&m2,&y2);
    if( d1<1 || d2<1 || d1>31 || d2>31 || m1<1 || m2<1 || m1>12 || m2>12 || y2>y1 )
    {
        printf("Enter a valid date next time.!");
        exit (0);
    }
    //calculating c1.
    if(y2%4!=0 || m2!=2)
        c1=m[(m2-1)] - d2;
    else
    {
        c1= 29 - d2;
    }

    // now calculating c2.
    for(int i=m2;i<12;i++)
    {
        c2 += m[i];
    }
    
    // now calculating c3.
    for(int i=(y2+1);i<y1;i++)
    {
        if(i%4!=0)
            c3 +=365;
        else
        {
            c3 += 366;
            k+=1;
        }
    }
    
    //now calculating c4.
    for(int i=0;i<(m1-1);i++)
    {
        c4 += m[i];
    }

    //now calculating c5.
    c5 = d1;

    //now finding total number of days
    int age= c1+c2+c3+c4+c5;
    printf("Your Age in days is:%d\n",age);

    //now converting it to number of years and number of months.

    int yr=(age-k)/365;
    int months=((age-k)%365)/31;
    int days=(age-(yr*365 +k)-(months*31));
    printf("You have been on earth for like %d Days %d Months %d Years.\n",days,months,yr);
    printf("Thank you");
    return 0;
}