A program that gives current weather for a given city name (with ALPHA-2 country code).

weather.py

import urllib
import json

def kelvin_to_celsius(temp):
    ''' 
    This function transforms temperature in Kelvins to Celsius
    '''
    return round(temp - 273.15)

def weather_search():
    '''
    This function requests info from API for data provided by the user and outputs the current weather 
    '''
    api_key = 'put your api id here'
    # you can get it for free by registering here: https://home.openweathermap.org/users/sign_up
    
    city_name = input('Please enter the city name: ')
    country = input('Please enter the country code (two letters): ')
    city_country = city_name + ',' + country
    
    query_params = {'APPID': api_key, 'q': city_country}

    encoded_params = urllib.parse.urlencode(query_params)
    final_link = 'http://api.openweathermap.org/data/2.5/weather?' + encoded_params
    
    try:
        url_open_in_json = urllib.request.urlopen(final_link)
    except urllib.error.URLError as e:
        print(e.reason)
    except urllib.error.HTTPError as e:
        print(e.reason)        
    else:
        data = json.load(url_open_in_json)

        temp = kelvin_to_celsius(data["main"]["temp"])
        feels_like = kelvin_to_celsius(data["main"]['feels_like'])
        sky = data["weather"][0]["main"]

        print(f"The weather in {city_country} is {sky}, the temperature (C) is {temp} (feels like {feels_like}).")