A simple python solution to the phone number word search problem here: https://www.youtube.com/watch?v=PIeiiceWe_w

getWordsFromPhoneNumber.py

#!/usr/bin/env python

import math

# Function: numberFromWord
#   - wordString: a String representative of the word
# Returns:
#   - number: an Integer representative of the screen based on map
def numberFromWord(wordStr):
    phoneMap = {"a": 2, "b": 2, "c": 2, 
                "d": 3, "e": 3, "f": 3,
                "g": 4, "h": 4, "i": 4,
                "j": 5, "k": 5, "l": 5,
                "m": 6, "n": 6, "o": 6,
                "p": 7, "q": 7, "r": 7, "s": 7,
                "t": 8, "u": 8, "v": 8,
                "w": 9, "x": 9, "y": 9, "z": 9}

    number = 0
    for char in range(len(wordStr)):
        number = number * 10
        number += phoneMap[wordStr[char]]

    return number


# Function: getWordsInPhoneNumber
#   - phoneNumberString: a String representation of a phone number
#   - wordStrings: an array of strings to search for in the number
# Returns:
#   - found: an array of Strings found within the phone number
def getWordsInPhoneNumber(phoneNumberString, wordStrings):
    found = []
    wordNumbers = []
    wordModulo = []
    phoneNumber = int(phoneNumberString)

    for index in range(len(wordStrings)):
        # This line is very smart. The wordModulo variable will serve as a
        #   mask later when searching for the word.
        wordModulo.append(10**len(wordStrings[index]))
        wordNumbers.append(numberFromWord(wordStrings[index]))

    # This while loop is where the fun happens, imo.
    #   Take the phone number as an integer, modulo it against wordModulo to
    #   leave a number the same size as the target word. Then, compare them.
    #   This way, the only comparison done is simple integer equals. Add the
    #   word if they're equal. After checking all the words this way, remove
    #   the last digit and repeat. Could easily pop the found words to reduce
    #   the number of searches when a word is found.
    while phoneNumber != 0:
        for index in range(len(wordNumbers)): 
            if phoneNumber % wordModulo[index] == wordNumbers[index]:
                found.append(wordStrings[index])
        phoneNumber = int(phoneNumber / 10)

    return found

def test():
    testWords = ["cab", "car", "yyz"]
    print("Test words:")
    for word in testWords:
        print("%s: %d" % (word, numberFromWord(word)))

    testPhoneNumber="122276789"
    print("Test phone number: %s" % testPhoneNumber)

    print(getWordsInPhoneNumber(testPhoneNumber, testWords))

if __name__ == "__main__":
    test()