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Recursive implementation of LCS (Lowest Common Subsequence) problem. Live Preview :- http://codepad.org/WWGCWVzJ
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#include<stdio.h> | |
int max(int a, int b) | |
{ | |
return (a > b)? a : b; | |
} | |
/* Returns length of LCS for X[0..m-1], Y[0..n-1] */ | |
int lcs( char *X, char *Y, int m, int n ) | |
{ | |
if (m == 0 || n == 0) | |
return 0; | |
if (X[m-1] == Y[n-1]) | |
return 1 + lcs(X, Y, m-1, n-1); | |
else | |
return max(lcs(X, Y, m, n-1), lcs(X, Y, m-1, n)); | |
} | |
int main() | |
{ | |
char X[] = "GGXATAB"; | |
char Y[] = "GXTXAYB"; | |
int m = strlen(X); | |
int n = strlen(Y); | |
printf("Length of LCS is %d\n", lcs( X, Y, m, n ) ); | |
return 0; | |
} |
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