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Stepic решение. 1.5 Решение систем линейных алгебраических уравнений
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#include<iostream> | |
#include <math.h> | |
#include <stdlib.h> | |
using namespace std; | |
int main() | |
{ | |
int i, j, n, m; | |
cout.precision(16); //set precision | |
cout.setf(ios::fixed); | |
cin >> n; | |
cin >> m; | |
m+=1; | |
double **matrix = new double *[n]; | |
for (i=0; i<n; i++) | |
matrix[i] = new double [m]; | |
for (i = 0; i<n; i++) | |
for (j = 0; j<m; j++) { | |
cin >> matrix[i][j]; | |
} | |
if (n >= m) { | |
cout << "NO"; | |
return 0; | |
} | |
//Метод Гаусса | |
//Прямой ход, приведение к верхнетреугольному виду | |
double tmp, xx[m]; | |
int k; | |
for (i=0; i<n; i++) { | |
tmp=matrix[i][i]; | |
for (j=n;j>=i;j--) | |
matrix[i][j]/=tmp; | |
for (j=i+1;j<n;j++) | |
{ | |
tmp=matrix[j][i]; | |
for (k=n;k>=i;k--) | |
matrix[j][k]-=tmp*matrix[i][k]; | |
} | |
} | |
/*обратный ход*/ | |
xx[n-1] = matrix[n-1][n]; | |
for (i=n-2; i>=0; i--) { | |
xx[i] = matrix[i][n]; | |
for (j=i+1;j<n;j++) { | |
xx[i]-=matrix[i][j]*xx[j]; | |
if (isnan(xx[i])) { | |
cout << "NO"; | |
return 0; | |
} | |
} | |
} | |
int isExist = true; | |
for (i=0; i<m;i++) { | |
if (isnan(xx[i])) { | |
isExist = false; | |
} | |
} | |
if (!isExist) { | |
cout << "NO"; | |
return 0; | |
} | |
if (n != m-1) { | |
cout << "INF"; | |
return 0; | |
} | |
//Выводим решения | |
cout << "YES\n"; | |
for (i=0; i<n; i++) | |
cout << xx[i] << " "; | |
cout << endl; | |
delete[] matrix; | |
return 0; | |
} |
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