Project Euler #1.java

/**Problem1:If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. 
The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
*/



/**
 * Created by Bebo on 6/16/2017.
 */
public class ex {
    public static void main(String[] args) {
        final int MAX = 1000;
        int threeMul = 0;
        int fiveMul = 0;
        int sum = 0;


        int natNums [] = new int[MAX];

        for (int i=0; i<MAX; i++){
            natNums[i] = i;
        }

        for (int j=0; j<MAX; j++){
            if(natNums[j] % 3 == 0){
                threeMul += natNums[j];
            }
            if (natNums[j] % 5 == 0){
                fiveMul += natNums[j];
            }
        }
        sum = threeMul + fiveMul;
        System.out.println(threeMul);
        System.out.println(fiveMul);
        System.out.println(sum);



    }

}