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August 14, 2012 03:35
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# Copyright (C) 2001-2009, Parrot Foundation. | |
=head1 NAME | |
examples/benchmarks/primes.pasm - Calculate prime numbers < 5000 | |
=head1 SYNOPSIS | |
% time ./parrot examples/benchmarks/primes.pasm | |
=head1 DESCRIPTION | |
Calculates all the prime numbers up to 5000 and prints out the number | |
of primes, the last one found, and the time taken. | |
=cut | |
.loadlib 'math_ops' # cmod is a dynop | |
.sub 'main' :main | |
# P1 holds the number we're currently checking for primality | |
new $P1, 'Integer' | |
set $P1, 1 | |
# P2 holds the highest number we want to check for primality | |
new $P2, 'Integer' | |
set $P2, 17619 | |
new $P6, 'Integer' | |
set $P6, 0 | |
new $P7, 'Integer' | |
print "N primes up to " | |
print $P2 | |
print " is: " | |
time $N10 | |
# P1 counts up to P2 | |
# P3 counts from 2 up to P4 (P1/2) | |
new $P3, 'Integer' | |
REDO: | |
set $P3, 2 | |
div $P4, $P1, 2 | |
# Check if P3 is a factor of P1 | |
LOOP: | |
cmod $P5, $P1, $P3 | |
if $P5, OK | |
# We've found a factor, so it can't be a prime and | |
# we can skip right out of this loop and to the next number | |
branch NEXT | |
OK: | |
inc $P3 | |
le $P3, $P4, LOOP | |
# We haven't found a factor so it must be a prime | |
inc $P6 | |
assign $P7, $P1 | |
# print I1 | |
# print "\n" # to get them all | |
# Move on to the next number | |
NEXT: | |
inc $P1 | |
le $P1, $P2, REDO | |
time $N11 | |
say $P6 | |
print "last is: " | |
say $P7 | |
sub $N11, $N10 | |
print "Elapsed time: " | |
say $N11 | |
.end | |
=head1 SEE ALSO | |
F<examples/benchmarks/primes.c>, | |
F<examples/benchmarks/primes_i.pasm>, | |
F<examples/benchmarks/primes.pl>, | |
F<examples/benchmarks/primes.rb>, | |
F<examples/benchmarks/primes2_p.pasm>, | |
F<examples/benchmarks/primes2.c>, | |
F<examples/benchmarks/primes2.pir>, | |
F<examples/benchmarks/primes2.py>. | |
=cut | |
# Local Variables: | |
# mode: pir | |
# fill-column: 100 | |
# End: | |
# vim: expandtab shiftwidth=4 ft=pir: |
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