Find the max of 2 numbers without any condition: if-else-clause, ternary operator, third-party library or core implementation.

max.js

/**
 * The only difference here is that sign(0) = 1
 */
let sign = a => {
  let signBit = a >>> 31;
  return signBit * -1 + (1 - signBit) * 1;
};

let abs = a => a * sign(a);

/**
 * (min + max + max - min) / 2 = 2 * max / 2 = max
 */
let max = (a, b) => (a + b + abs(a - b)) / 2;