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| Require Import List. | |
| Import ListNotations. | |
| Inductive ForallT {A : Type} (P : A -> Type) : list A -> Type := | |
| | ForallT_nil : ForallT P [] | |
| | ForallT_cons (x : A) (l : list A) : P x -> ForallT P l -> ForallT P (x :: l). | |
| Hint Constructors ForallT : core. | |
| Definition fold_ForallT {A R : Type} {P: A -> Type} | |
| (hnil : R) (hcons : forall (a : A), P a -> R -> R) | |
| xs (pxs : ForallT P xs): R := | |
| ForallT_rect A P (fun _ _ => R) hnil (fun x xs px _ => hcons x px) xs pxs. | |
| Definition fold_ForallT_manual {A R : Type} {P: A -> Type} | |
| (hnil : R) (hcons : forall (a : A), P a -> R -> R) : | |
| forall xs, ForallT P xs -> R := | |
| fix F xs pxs := | |
| match pxs return _ with | |
| | ForallT_nil _ => hnil | |
| | ForallT_cons _ x xs px pxs => hcons x px (F xs pxs) | |
| end. | |
| (** To be able to reuse lemmas on Forall, show that ForallT is equivalent to Forall for predicates in Prop. | |
| The proof is a bit subtler than you'd think because it can't look into Prop | |
| to produce proof-relevant part of the result (and that's why I can't inversion until very late. | |
| *) | |
| Lemma ForallT_Forall {X} (P: X -> Prop) xs: (ForallT P xs -> Forall P xs) * (Forall P xs -> ForallT P xs). | |
| Proof. | |
| split; (induction xs; intro H; constructor; [|apply IHxs]); inversion H; trivial. | |
| Qed. |
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