Created
December 9, 2015 18:42
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Method to return the nth value of the Fibonacci sequence
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# PHI - Some greek number | |
PHI = Rational(610,377).to_f | |
# Negative inverse of PHI | |
I_PHI = -Rational(1, PHI).to_f | |
# Square root of 5 | |
SQRT_5 = 5 ** 0.5 | |
# Fibonacci value for given number x | |
# | |
# x - An Integer representing the nth number in the fibonacci sequence | |
# | |
# Returns an Integer | |
def fibonacci(n) | |
((PHI**n - I_PHI**n) / SQRT_5).round | |
end |
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require "rspec" | |
require "fibonacci" | |
# Bunch of tests to prove I'm right... | |
describe "#fibonacci" do | |
it "returns 0 if x is 0" do | |
expect(fibonacci(0)).to eql(0) | |
end | |
it "returns 1 if x is 1" do | |
expect(fibonacci(1)).to eql(1) | |
end | |
it "returns 1 if x is 2" do | |
expect(fibonacci(2)).to eql(1) | |
end | |
it "returns 2 if x is 3" do | |
expect(fibonacci(3)).to eql(2) | |
end | |
it "returns 3 if x is 4" do | |
expect(fibonacci(4)).to eql(3) | |
end | |
it "returns 5 if x is 5" do | |
expect(fibonacci(4)).to eql(3) | |
end | |
it "returns 34 if x is 9" do | |
expect(fibonacci(9)).to eql(34) | |
end | |
end |
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