Open an app shortcut programmatically

open_shortcut.m

- (void)openShortcut:(SBSApplicationShortcutItem *)shortcutItem {
	
	UIHandleApplicationShortcutAction *openAction = [[UIHandleApplicationShortcutAction alloc] initWithSBSShortcutItem:shortcutItem];
	
	NSDictionary *activationOptions = @{
		@"__ActivateSuspended" : [NSNumber numberWithBool:(shortcutItem.activationMode == 1)],
		@"__Actions": @[
			openAction
		],
		@"__PromptUnlockDevice" : [NSNumber numberWithBool:YES],
		@"__LaunchOrigin": @"__SBLaunchOriginShortcutItem"
	};
	
	FBSOpenApplicationOptions *applicationOptions = [FBSOpenApplicationOptions optionsWithDictionary: activationOptions];
	
	FBSOpenApplicationService *openService = [[FBSOpenApplicationService alloc] init];
	[openService openApplication: shortcutItem.bundleIdentifierToLaunch withOptions:applicationOptions completion:nil];
}

Only work on jailbreak device?