alternative code

msgpack.coffee

calc = (buf,idx,i) ->
    if i != 2 then buf[idx++] * Number("0x1" + [1..i].map(j) -> "0") + calc(buf,idx, i - 2) else buf[idx++]
return num * 0x100000000000000 + calc(buf,idx,i)

## Original, lines 343 - 350 ##
return num * 0x100000000000000 +
	buf[idx++] * 0x1000000000000 +
	buf[idx++] * 0x10000000000 +
	buf[idx++] * 0x100000000 +
	buf[idx++] * 0x1000000 +
	buf[idx++] * 0x10000 +
	buf[idx++] * 0x100 +
	buf[idx++]