ChathuraGH

// console.log([...permutate(['1', '2', '3'], 2)])
// console.log([...permutate(['1', '2', '3'], 3)])

function* permutate(items, count) {
  yield* req([])

  function* req(array) {
    if (array.length == count) {
      yield array.join('')
      return

ChathuraGH

 function chunkString (str, len) {
  const size = Math.ceil(str.length/len)
  const r = Array(size)
  let offset = 0
  
  for (let i = 0; i < size; i++) {
    r[i] = str.substr(offset, len)
    offset += len
  }
  

ChathuraGH

function loadjscssfile(filename, filetype){
 if (filetype=="js"){ //if filename is a external JavaScript file
  var fileref=document.createElement('script')
  fileref.setAttribute("type","text/javascript")
  fileref.setAttribute("src", filename)
 }
 else if (filetype=="css"){ //if filename is an external CSS file
  var fileref=document.createElement("link")
  fileref.setAttribute("rel", "stylesheet")
  fileref.setAttribute("type", "text/css")

ChathuraGH

//Split the string with the spread ... operator instead of .split(''):

'🌯🌯🍣🍻'.split('')
//=> ["\ud83c", "\udf2f", "\ud83c", "\udf2f", "\ud83c", "\udf63", "\ud83c", "\udf7b"]
//vs

[...'🌯🌯🍣🍻']
//=> ["🌯", "🌯", "🍣", "🍻"]
//vs

ChathuraGH

function Char_Count(str1) {
    var chars = {};
    str1.replace(/\S/g, function(l){chars[l] = (isNaN(chars[l]) ? 1 : chars[l] + 1);});
    return chars;
}

var myString = "This is my String";
console.log(Char_Count(myString));

ChathuraGH

function countChrOccurence ('hello') {
 let charMap = new Map();
 const count = 0;
  for (const key of str) {
   charMap.set(key,count); // initialize every character with 0. this would make charMap to be 'h'=> 0, 'e' => 0, 'l' => 0, 
  }

  for (const key of str) {
    let count = charMap.get(key);
    charMap.set(key, count + 1);

ChathuraGH

function countChar(str) {
    let myObj= {};
    for (let s of str) {
        if ( myObj[s] ? myObj[s].count ++ : myObj[s] = { count : 1 } );
    }
    return myObj;
}

var charCount = countChar('abcceddd');

ChathuraGH

let str = "atul kumar srivastava";
let obj ={};
for(let s of str)if(!obj[s])obj[s] = 1;else obj[s] = obj[s]  + 1;
console.log(obj)



//source 
// https://stackoverflow.com/questions/19480916/count-number-of-occurrences-for-each-char-in-a-string
// https://stackoverflow.com/a/60648545/13861187

ChathuraGH

const k = 5;
const dict = {
  "x" : 1,
  "y" : 6,
  "z" : 9,
  "a" : 5,
  "b" : 7,
  "c" : 11,
  "d" : 17,
  "t" : 3

ChathuraGH

const sortObjectByValues = (dict: { [key: string]: number }, direction: 'asc'| 'desc' = 'asc') => {
  return Object.fromEntries(Object.entries(dict).sort((a, b) => {
    if (direction === 'asc') {
      return a[1] - b[1]
    }
    return b[1] - a[1]
  }))
}