ChathuraGH

This is gist. 
There are many like it, but this one is mine. 
It is my life. 
I must master it as I must master my life. 
Without me gist is useless. 
Without gist, I am useless.

ChathuraGH

var dict = {
  "x": 1,
  "y": 6,
  "z": 9,
  "a": 5,
  "b": 7,
  "c": 11,
  "d": 17,
  "t": 3
};

ChathuraGH

function sort_object(obj) {
    items = Object.keys(obj).map(function(key) {
        return [key, obj[key]];
    });
    items.sort(function(first, second) {
        return second[1] - first[1];
    });
    sorted_obj={}
    $.each(items, function(k, v) {
        use_key = v[0]

ChathuraGH

class DictUtils {
    static entries(dictionary) {

        try {

            //ECMAScript 2017 and higher, better performance if support
            return Object.entries(dictionary);

        } catch (error) {

ChathuraGH

let s = 'hello';
var result = [...s].reduce((a, e) => { a[e] = a[e] ? a[e] + 1 : 1; return a }, {}); 
console.log(result); // {h: 1, e: 1, l: 2, o: 1}

ChathuraGH

function withAMap(str) {
    // A map for the character=>count mappings
    const counts = new Map();

    // Loop through the string...
    for (const ch of str) {
        // Get the count for it, if we have one; we'll get `undefined` if we don't
        // know this character yet. Using nullish coalescing (`??`), we can turn
        // that `undefined` into a `0`. (In obsolete environments that don't

ChathuraGH

function sortObj(obj) {
    // Sort object as list based on values
    return Object.keys(obj).map(k => ([k, obj[k]])).sort((a, b) => (b[1] - a[1]))
}



//source 
//https://stackoverflow.com/questions/25500316/sort-a-dictionary-by-value-in-javascript
//https://stackoverflow.com/a/74250133/13861187

ChathuraGH

const sortObjectByValues = (dict: { [key: string]: number }, direction: 'asc'| 'desc' = 'asc') => {
  return Object.fromEntries(Object.entries(dict).sort((a, b) => {
    if (direction === 'asc') {
      return a[1] - b[1]
    }
    return b[1] - a[1]
  }))
}

ChathuraGH

const k = 5;
const dict = {
  "x" : 1,
  "y" : 6,
  "z" : 9,
  "a" : 5,
  "b" : 7,
  "c" : 11,
  "d" : 17,
  "t" : 3

ChathuraGH

let str = "atul kumar srivastava";
let obj ={};
for(let s of str)if(!obj[s])obj[s] = 1;else obj[s] = obj[s]  + 1;
console.log(obj)



//source 
// https://stackoverflow.com/questions/19480916/count-number-of-occurrences-for-each-char-in-a-string
// https://stackoverflow.com/a/60648545/13861187