Created
          February 28, 2023 14:13 
        
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    Given a list of numbers, return all groups of repeating consecutive numbers
  
        
  
    
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  | const repeatedGroups = (numbers: number[]) => | |
| numbers | |
| .reduce<number[][]>( | |
| (acc, num) => (acc.length === 0 || !acc[acc.length - 1].includes(num) ? [...acc, [num]] : [...acc.slice(0, acc.length - 1), [...acc[acc.length - 1], num]]), | |
| [] | |
| ) | |
| .filter(nums => nums.length > 1) | 
  
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