Created
January 16, 2017 19:43
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N = 10 | |
λ=-0.1; tEnd=1000. | |
tThreshold = 0.1 | |
u0 = zeros(4 * N) | |
for i in 1 : N | |
u0[2*i - 1] = -5. + 10.*rand() | |
u0[2*i] = -5. + 10.*rand() | |
u0[2*N + 2*i - 1] = 0. | |
u0[2*N + 2*i] = 1. | |
end | |
f0= function (t, u, p, du) | |
N, λ = Int(p[1]), p[2] | |
@inbounds for k = 1 : N | |
du[2*N + 2*k - 1] = -u[2*N + 2*k] | |
du[2*N + 2*k] = u[2*N + 2*k - 1] | |
fx, fy = 0.0, 0.0 | |
for i = 1 : N | |
if i != k | |
rx = u[2*k-1] - u[2*i-1] | |
ry = u[2*k] - u[2*i] | |
nx = u[2*N+2*i-1] | |
ny = u[2*N+2*i] | |
a = rx*nx + ry*ny | |
rinv = 1. / √(rx*rx + ry*ry) | |
rinv3 = rinv * rinv * rinv | |
rinv5 = rinv3 * rinv * rinv | |
rinv13 = rinv5 * rinv5 * rinv3 | |
fx -= rx * rinv3 | |
fy -= ry * rinv3 | |
fx += 3*a^2 * rx * rinv5 | |
fy += 3*a^2 * ry * rinv5 | |
fx -= rx * rinv13 | |
fy -= ry * rinv13 | |
end | |
du[2*k - 1] = λ * fx + u[2*N + 2*k - 1] | |
du[2*k] = λ * fy + u[2*N + 2*k] | |
end | |
end | |
end | |
using DifferentialEquations, ODEInterfaceDiffEq | |
f = ParameterizedFunction(f0, [N, λ]) | |
eq = ODEProblem(f, u0, (0., tEnd)) | |
sol = solve(eq,Rosenbrock23()) | |
sol = solve(eq,CVODE_BDF()) | |
sol = solve(eq,radau()) | |
using Plots; plot(sol,vars=[1],lw=1) |
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