Created
December 8, 2016 02:35
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(* If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. | |
* | |
* Find the sum of all the multiples of 3 or 5 below 1000. | |
*) | |
let rec find_multiples counter accum = | |
let x = 3 * counter in | |
let y = 5 * counter in | |
if ((List.exists (fun a -> x == a) accum)) then | |
match (y < 1000) with | |
| true -> find_multiples (counter+1) ( y :: accum) | |
| false -> find_multiples (counter+1) accum | |
else | |
match (x < 1000, y < 1000) with | |
| (true, true) -> find_multiples (counter+1) (x :: y :: accum) | |
| (true,false) -> find_multiples (counter+1) (x :: accum) | |
| (false,true) -> find_multiples (counter+1) (y :: accum) | |
| (false,false) -> accum | |
;; | |
let result = find_multiples 1 [];; | |
List.map print_int result ;; | |
Printf.printf "\n";; | |
print_int (List.fold_left (+) (0) result );; |
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