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ES5 "Classes": Methods in Function() vs Prototype
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// Version 1 | |
// In this version, makeSound will be redeclared for every instance. | |
// Not horrible but can cause more memory utilization than needed. | |
function Animal(type, name, sound) { | |
this.type = type; | |
this.name = name; | |
this.sound = sound; | |
this.makeSound = function() {return "The " + this.type + " named " + this.name + " goes " + this.sound + "!";}; | |
} | |
// Version 2 | |
// In this version, makeSound will be only be declared once | |
function AnimalSkinny(type, name, sound) { | |
this.type = type; | |
this.name = name; | |
this.sound = sound; | |
} | |
AnimalSkinny.prototype.makeSound = function() { | |
return "The " + this.type + " named " + this.name + " goes " + this.sound + "!"; | |
}; | |
var frogFat = new Animal('frog', 'Conner', 'ribbit'); | |
var frogSkinny = new AnimalSkinny('frog', 'Conner', 'ribbit'); | |
console.log("Emitting frogFat", frogFat); | |
console.log("frogFat spoke:"+frogFat.makeSound()); | |
console.log("Note how the method is visible and declared to the class instance."); | |
console.log("\n\n"); | |
console.log("Emitting frogSkinny", frogSkinny); | |
console.log("frogSkinny spoke:"+frogSkinny.makeSound()); | |
console.log("Note how the method is not declared on the class instance but under the protoObject"); |
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