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Leetcode: two_sum problem in Rust
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// /* | |
// Given an array of integers, return indices of the two numbers such that they add up to a specific target. | |
// You may assume that each input would have exactly one solution, and you may not use the same element twice. | |
// Example: | |
// Given nums = [2, 7, 11, 15], target = 9, | |
// Because nums[0] + nums[1] = 2 + 7 = 9, | |
// return [0, 1]. | |
// */ | |
pub fn two_sum(nums: Vec<i32>, target: i32) -> Vec<i32> { | |
for (idx1, &v) in nums.iter().enumerate() { | |
let offset = idx1 + 1; | |
for (idx2, &v2) in nums[offset..].iter().enumerate() { | |
if v + v2 == target { | |
return vec![idx1 as i32, (idx2 + offset) as i32]; | |
} | |
} | |
} | |
vec![] | |
} | |
#[cfg(test)] | |
mod tests { | |
use super::*; | |
#[test] | |
fn can_find_sums() { | |
let test_vec = vec![2, 7, 11, 15]; | |
let test_target = 9; | |
let expected_result: Vec<i32> = vec![0, 1]; | |
assert_eq!(expected_result, two_sum(test_vec, test_target)); | |
} | |
#[test] | |
fn can_find_sums_2() { | |
let test_vec = vec![3,2,4]; | |
let test_target = 6; | |
let expected_result: Vec<i32> = vec![1, 2]; | |
assert_eq!(expected_result, two_sum(test_vec, test_target)); | |
} | |
} |
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