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My solution to CS50 pset2 - "Hail, Caesar!"
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#include <stdio.h> | |
#include <cs50.h> | |
#include <string.h> | |
#include <ctype.h> | |
/** | |
* Caesar.c | |
* A program that encrypts messages using Caesar’s cipher. Your program must | |
* accept a single command-line argument: a non-negative integer. Let’s call it | |
* k for the sake of discussion. If your program is executed without any | |
* command-line arguments or with more than one command-line argument, your | |
* program should yell at the user and return a value of 1. | |
* | |
* */ | |
int main(int argc, string argv[]) | |
{ | |
// check for 2 arguments only | |
if (argc != 2) | |
{ | |
printf("Nope\n"); | |
return 1; | |
} | |
// once I check for correct argv put key into an int k | |
int k = atoi(argv[1]); | |
// check if the integer is non-negative | |
if (k < 0) | |
{ | |
printf("Nope\n"); | |
return 1; | |
} | |
else | |
{ | |
// prompt user for a code to encrypt | |
string code = GetString(); | |
for (int i = 0, n = strlen(code); i < n; i++) | |
{ | |
//check if the letter is uppercase or lowercase then convert | |
if islower(code[i]) | |
printf("%c", (((code[i] + k) - 97) % 26) + 97); | |
else if isupper(code[i]) | |
printf("%c", (((code[i] + k) - 65) % 26) + 65); | |
//if neither then just print whatever it is | |
else | |
printf("%c", code[i]); | |
} | |
printf("\n"); | |
return 0; | |
} | |
} |
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idk
i'm also getting thi with similiar code
were u able to do it?