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Last active February 7, 2020 16:48
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C | main
#include <stdio.h>
int main(void)
{
int age = 15;
(age == 15) ? printf("You're 15 years old. \n") : printf("You're not 15 years old.\n");
return 0;
}
/*
print in console: You're 15 years old.
Program ended with exit code: 0
*/
#include <stdio.h>
int main(void)
{
int age = 15;
int he_is_fifteen = -1;
he_is_fifteen = (age == 15) ? 1 : 0;
printf("He is fifteen = %d\n" , he_is_fifteen);
return 0;
}
/*
print in console: He is fifteen = 1
Program ended with exit code: 0
*/
#include <stdio.h>
int main(void)
{
int i = 0;
while(i < 20)
{
printf("All is good in the hood ! \n");
i++;
//++ incrementation guarantees that the loop continues the operation not undefinetly but untill it fulfill the condition.
}
return 0;
}
/*
print in console:
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
All is good in the hood !
---------
* 20 times because we started from 0.
---------
Program ended with exit code: 0
*/
#include <stdio.h>
int main(void)
{
int i = 6;
do{
// This condition guarantees we get into the loop at least once before we find out if we meet the condition or not.
printf("Where u at? \n");
i++;
}
while(i < 5);
return 0;
}
/*
print in console: Where u at?
Program ended with exit code: 0
*/
#include <stdio.h>
int main(void)
{
int age = 111;
switch(age)
{
case 0:
printf("You are 0 year old.\n");
break;
case 15:
printf("You are 15 years old.\n");
default:
printf("You are neither 0 nor 15 years old.\n");
}
return 0;
}
/*
print in console: You are neither 0 nor 15 years old.
Program ended with exit code: 0
*/
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