Remove all arranged subviews from UIStackView at once

UIStackView+removeAll.swift

import UIKit

extension UIStackView {
    
    func removeAllArrangedSubviews() {
        
        let removedSubviews = arrangedSubviews.reduce([]) { (allSubviews, subview) -> [UIView] in
            self.removeArrangedSubview(subview)
            return allSubviews + [subview]
        }
        
        // Deactivate all constraints
        NSLayoutConstraint.deactivate(removedSubviews.flatMap({ $0.constraints }))
        
        // Remove the views from self
        removedSubviews.forEach({ $0.removeFromSuperview() })
    }
}

can you please modify to remove the first inserted or last inserted arrangedView. It will be a great help.

Gotcha brute force :P

extension UIStackView {
    
    func removeFirstArrangedView() {
        
        for item in arrangedSubviews {
            removeArrangedSubview(item)
            item.removeFromSuperview()
            break
        }
    }
   
   var i=1
   func removeLastArrangedView() {
        
           
    for item in arrangedSubviews {
        if i == arrangedSubviews.count {
            removeArrangedSubview(item)
            item.removeFromSuperview()
        }
        i+=1
    }
   } 
}

Couldn't you deactivate the constraints and removeFromSuperview inside the nextPartialResult closure?
That way you wouldn't need to run through the whole array 3 times.

Something like

@discardableResult
func removeAllArrangedSubviews() -> [UIView] {
        let removedSubviews = arrangedSubviews.reduce([]) { (removedSubviews, subview) -> [UIView] in
            self.removeArrangedSubview(subview)
            NSLayoutConstraint.deactivate(subview.constraints)
            subview.removeFromSuperview()
            return removedSubviews + [subview]
        }
        return removedSubviews
    }

If someone will confuse on how to use magpali code then here's the same:

extension UIStackView {
    @discardableResult func removeAllArrangedSubviews() -> [UIView] {
        let removedSubviews = arrangedSubviews.reduce([]) { (removedSubviews, subview) -> [UIView] in
            self.removeArrangedSubview(subview)
            NSLayoutConstraint.deactivate(subview.constraints)
            subview.removeFromSuperview()
            return removedSubviews + [subview]
        }
        return removedSubviews
    }
}

Or you can do it like this:

stack.arrangedSubviews
            .filter({ $0 is SomeView })
            .forEach({ $0.removeFromSuperview() })

Swift 4/5
https://gist.github.com/yasirmturk/0b47d18a30722902a9a4aaad05d1794a

Please corret me if I'm wrong but from my understanding you could simply do the following to remove all arrangedSubviews:

extension UIStackView {
    func removeAllArrangedSubviews() {
        arrangedSubviews.forEach {
            self.removeArrangedSubview($0)
            NSLayoutConstraint.deactivate($0.constraints)
            $0.removeFromSuperview()
        }
    }
}

Worked like a charm 👍

Just the SnapKit version:

import UIKit
import SnapKit

extension UIStackView {
    
    func removeArrangedSubviews() {
        guard !arrangedSubviews.isEmpty else { return }
        let subviewsToRemove = arrangedSubviews.reduce([]) { allSubviews, subview -> [UIView] in
            self.removeArrangedSubview(subview)
            return allSubviews + [subview]
        }
        subviewsToRemove.forEach { subview in
            subview.snp.removeConstraints()
            subview.removeFromSuperview()
        }
    }
}