Skip to content

Instantly share code, notes, and snippets.

@DmitrySoshnikov
Last active November 8, 2024 16:06
Show Gist options
  • Save DmitrySoshnikov/1239097 to your computer and use it in GitHub Desktop.
Save DmitrySoshnikov/1239097 to your computer and use it in GitHub Desktop.
Shunting yard algorithm
/**
* Shunting yard algorithm
* See: http://en.wikipedia.org/wiki/Shunting_yard_algorithm
*
* Converts infix notation to postfix notation
*
* by Dmitry Soshnikov <[email protected]>
* MIT Style License
*
* (C) 2011, updated on 2020
*/
// helper, top element of an array w/o removing it
Array.prototype.peek = function () {
return this[this.length - 1];
};
// operators set
const operators = {"+": 1, "-": 1, "*": 1, "/": 1};
// associations (left / right) sets
const leftAssoc = {"*": 1, "/": 1, "%": 1, "+": 1, "-": 1};
const rightAssoc = {"=": 1, "!": 1};
/**
* precedenceOf
*
* precedence operators associativity
* 1 ! right to left
* 2 * / % left to right
* 3 + - left to right
* 4 = right to left
*/
const precedenceOf = {
"!": 4,
"*": 3,
"/": 3,
"%": 3,
"+": 2,
"-": 2,
"=": 1
};
/**
* Shunting_yard_algorithm
* @param {String} string
*
* TODO:
* - support digits > 10
* - functions
*/
function shuntingYard(string) {
let output = [];
let stack = [];
for (let k = 0; k <string.length; k++) {
// current char
const ch = string[k];
// skip whitespaces
if (ch === " ") {
continue;
}
// if it's a number, add it to the output queue
if (/\d/.test(ch)) {
output.push(ch);
}
// TODO: if the token is a function token, then push it onto the stack
// TODO: if the token is a function argument separator (e.g., a comma):
// if the token is an operator, op1, then:
else if (ch in operators) {
const op1 = ch; // just for readability
// while ...
while (stack.length > 0) {
// ... there is an operator token, op2, at the top of the stack
const op2 = stack.peek();
if (op2 in operators && (
// and op1 is left-associative and its precedence is less than or equal to that of op2,
(op1 in leftAssoc && (precedenceOf[op1] <= precedenceOf[op2])) ||
// or op1 is right-associative and its precedence is less than that of op2,
(op1 in rightAssoc && (precedenceOf[op1] < precedenceOf[op2]))
)) {
// push op2 onto the output queue
output.push(stack.pop()); // op2
} else {
break;
}
}
// push op1 onto the stack
stack.push(op1);
}
// if the token is a left parenthesis, then push it onto the stack.
else if (ch === "(") {
stack.push(ch);
}
// if the token is a right parenthesis:
else if (ch === ")") {
let foundLeftParen = false;
// until the token at the top of the stack is a left parenthesis,
// pop operators off the stack onto the output queue
while (stack.length > 0) {
const c = stack.pop();
if (c === "(") {
foundLeftParen = true;
break;
} else {
output.push(c);
}
}
// if the stack runs out without finding a left parenthesis, then there are mismatched parentheses.
if (!foundLeftParen) {
throw new Error("Parentheses mismatched");
}
// TODO: if the token at the top of the stack is a function token, pop it onto the output queue.
}
else {
throw new Error(`Unknown token: ${ch}`);
}
}
// when there are no more tokens to read:
// while there are still operator tokens in the stack:
while (stack.length > 0) {
const c = stack.pop();
if (c === "(" || c === ")") {
throw new Error("Parentheses mismatched");
}
// push it to the output
output.push(c);
}
return output.join(" ");
}
// tests
console.log("2 + 2 + 2 ->", shuntingYard("2 + 2 + 2")); // 2 2 + 2 +
console.log("2 + 2 * 2 ->", shuntingYard("2 + 2 * 2")); // 2 2 2 * +
console.log("(2 + 2) * 2 ->", shuntingYard("(2 + 2) * 2")); // 2 2 + 2 *
console.log("2 / (4 * 2) ->", shuntingYard("2 / (4 * 2)")); // 2 4 2 * /
@syaleni
Copy link

syaleni commented Aug 21, 2020

Doesn't pass this test:
2 / (4 * 2) -> 2 4 2 *

@DmitrySoshnikov
Copy link
Author

@syaleni, thanks; fixed!

It's interesting to update a diff from 9 years ago, lol :)

@syaleni
Copy link

syaleni commented Sep 6, 2020 via email

@rofrol
Copy link

rofrol commented Apr 14, 2024

There is now arr.at(-1) instead of arr[arr.length - 1] for peek function.

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment