Dart's isolate test

isolate-test.dart

class Printer extends Isolate {
  main() {
    port.receive((message, replyTo) {
      if (message == null) port.close();
      else print(message);
    });
  }
}

main() {
  // first isolate process
  new Printer().spawn().then((port) {
    for (var message in ['Hello', 'from', 'other', 'isolate']) {
      port.send(message);  
    }
    port.send(null);
  });

  // second isolate process
  new Printer().spawn().then((port) {
    for (var message in ['*Hello', '*from', '*other', '*isolate']) {
      port.send(message);  
    }
    port.send(null);
  });
}

// Results (WTF?)

Hello
from
other
isolate
*Hello
*from
*other
*isolate

// Why the output is sequential but not parallel? How the Dart's processes' scheduler work?

Still it seems just a bug for me. Even being in a single (real, OS) thread, cooperative ("green", "light") threads (or "tasks", or "isolates" how they are called here) are usually managed by a scheduler. For example, Erlang also uses "green" lightweight processes and schedules them in parallel. Even in current JS with yield it's possible to have such cooperative tasks which are executed in parallel by the scheduler (see e.g. this one simple implementation: https://gist.github.com/1127536).

Usually when the spawn is used it means that something is running in a separate region and in parallel. In other case -- what for do I need to write this useless wrappers with isolate and spawn in order just to provide sequential code? Seems just a bug of the current version.

Hello. Here is my try - http://try-dart-lang.appspot.com/s/L5QU
Usually the result is not parallel, but one time (only one) I got the following result:

*Hello
*from
Hello
*other

MT is heavy to test)) - I tried to insert my sleep() method inside Isolate, but t no success.

isopov yes, really strange results. On my machine your tests often do not finish completely -- i.e. only output from first or second process, but sometimes -- both. So, definitely there are still bugs in this module. Thus, this is regardless whether I use your sleep function or comment it (btw, the sleep method you wrote is blocking).

This is outside the scope of the current conversation regarding light and heavy isolates. My question is more basic; the syntax is confusing me. What exactly are we passing in as an argument to "then"? I think mostly "(port)" is throwing me off.

new Printer().spawn().then((port) {
for (var message in ['Hello', 'from', 'other', 'isolate']) {
port.send(message);
}
port.send(null);
});

Ahh I see now that its an anonymous function, so once the Isolate is spawned the unnamed functions is called with port as the argument.

http://www.dartlang.org/articles/idiomatic-dart/

This makes no sense. spawn indicates there's an internal scheduler involved, which would make me believe the loops run in parallel causing results not to be in a sequence.

FreakTheMighty, right, it's an anonymous callback function.

kaisellgren, yes, the same I thought (after programming in Erlang and having implemented similar scheduled processes in JS with yield -- https://gist.github.com/1127536). However, after analyzing the source code of Dart's runtime library, I figured out that it's a design decision caused by impossibility of implementation of such parallel processes with using just setTimeout scheduling (you may check btw, my similar setTimeout processes -- https://gist.github.com/1103751). That is, callback process function should run to completeness and can't be interrupted in the middle. And exactly this cases sequential execution, but not parallel.

Recently I discussed the topic in Dart's mailing list: http://bit.ly/n3IUiT

@DmitrySoshnikov: as far as I know, most ES engines do not support yield, except *Monkey. Therefore, I also believe the Dart engineers decided it is not possible to support "parallel processes" in transcompiled JS and this is the outcome :(. By the way, I like https://gist.github.com/1127536, did something similar once as well :)