Created
April 29, 2020 01:08
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Simple implementation of the Probabilistic Serial fair division mechanism
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from fractions import Fraction | |
def probabilistic_serial(profile): | |
"input is a list of preference lists" | |
N = range(len(profile)) # agents | |
O = range(len(profile[0])) # items | |
supply = {o : Fraction(1,1) for o in O} | |
allocation = {(i,o) : Fraction(0,1) for i in N for o in O} | |
while any(supply.values()): | |
# in each iteration, at least one remaining item is fully depleted | |
eating = {} | |
eaters = {o : 0 for o in O} # number of agents eating each item | |
for i in N: | |
o_ = next((o for o in profile[i] if supply[o])) | |
eating[i] = o_ | |
eaters[o_] += 1 | |
# how much time until the first remaining item is depleted | |
time = min(supply[o] / eaters[o] for o in O if supply[o] and eaters[o]) | |
for i in N: | |
allocation[i,eating[i]] += time | |
supply[eating[i]] -= time | |
return allocation | |
# example from https://en.wikipedia.org/w/index.php?title=Probabilistic-serial_procedure&oldid=915874133#Example | |
allocation = probabilistic_serial([[0,1,2,3],[0,1,2,3],[1,0,3,2],[1,0,3,2]]) | |
for i in range(4): | |
print(str(i) + ": " + ", ".join([str(float(allocation[i,o])) for o in range(4)])) | |
# produces | |
# 0: 0.5, 0.0, 0.5, 0.0 | |
# 1: 0.5, 0.0, 0.5, 0.0 | |
# 2: 0.0, 0.5, 0.0, 0.5 | |
# 3: 0.0, 0.5, 0.0, 0.5 |
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