A script to calculate the distribution of weekdays for each date (1st to 31st) for every month in 2024. Find out how often each date falls on a Saturday or Sunday. This is to avoid Revolut extra charges for weekends.

weekend.py

import calendar

def count_weekends(year):
    # Dictionary to hold the count of Saturdays and Sundays for each date
    weekend_counts = {date: 0 for date in range(1, 32)}

    # Process each month and each date in the month
    for month in range(1, 13):
        # Get the number of days in the month
        num_days = calendar.monthrange(year, month)[1]
        for day in range(1, num_days + 1):
            # Get the weekday (0=Monday, 6=Sunday)
            weekday = calendar.weekday(year, month, day)
            # If it's Saturday (5) or Sunday (6), increment the count
            if weekday == 5 or weekday == 6:
                weekend_counts[day] += 1

    # Print the results
    for date in sorted(weekend_counts):
        print(f"Date {date}: {weekend_counts[date]} weekends")

    # Find the date with the minimum weekends
    min_weekends = min(weekend_counts.values())
    least_likely_dates = [date for date, count in weekend_counts.items() if count == min_weekends]

    print(f"\nDates that are least likely to be a weekend in {year}: {least_likely_dates}")

# Year to analyze
year = 2024
count_weekends(year)

https://codehs.com/sandbox/id/python-3-pEvSi5 working sandbox