Write a program that prints the next 20 leap years.

leap_years.py

# Input
CURRENT_YEAR = 2017
NOF_LEAP_YEARS = 20

# Functions
def is_leap_year(year):
    if year % 4 > 0:
        return False
    elif year % 100 > 0:
        return True
    elif year % 400 > 0:
        return False
    else:
        return True

def print_next_leap_years(current_year, nof_leap_years):
    nof_leap_years_found = 0

    while nof_leap_years_found < nof_leap_years:
        if is_leap_year(current_year):
            nof_leap_years_found += 1
            print(current_year)

        current_year += 1
        
def print_next_leap_years_with_recursion(current_year, nof_leap_years, nof_leap_years_found = 0):
    if is_leap_year(current_year):
        nof_leap_years_found += 1
        print(current_year)    

    if nof_leap_years_found < nof_leap_years:
        print_next_leap_years_with_recursion(current_year + 1, nof_leap_years, nof_leap_years_found)

# Main
print_next_leap_years(CURRENT_YEAR, NOF_LEAP_YEARS)
print_next_leap_years_with_recursion(CURRENT_YEAR, NOF_LEAP_YEARS)
    

Cool! Try Lua for a challenge... ;)