beesandbombs

float[][] result;
float t, c;

float ease(float p) {
  p = c01(p);
  return 3*p*p - 2*p*p*p;
}

float ease(float p, float g) {
  p = c01(p);

thecodewarrior

chriseidhof

// Run any SwiftUI view as a Mac app.

import Cocoa
import SwiftUI

NSApplication.shared.run {
    VStack {
        Text("Hello, World")
        	.padding()
            .background(Capsule().fill(Color.blue))

wtsnz

import SwiftUI

struct ContentView: View {

    @State var now = Date()
    @State var showWindow = false
    @State var text: String = ""

    let timer = Timer.publish(every: 1, on: .current, in: .common).autoconnect()

joepie91

You don't need a blockchain.

If you're reading this, you probably suggested to somebody that a particular technical problem could be solved with a blockchain.

Blockchains aren't a desirable thing; they're defined by having trustless consensus, which necessarily has to involve some form of costly signaling to work; that's what prevents attacks like sybil attacks.

In other words: blockchains must be expensive to operate, to work effectively. This makes it a last-resort solution, when you truly have no other options available for solving your problem; in almost every case you want a cheaper and less complex solution than a blockchain.

In particular, if your usecase is commercial, then you do not need or want trustless consensus. This especially includes usecases like supply chain tracking, ticketing, and so on. The whole *p