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Check when an element comes into view (jQuery)
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function isOnScreen(elem) { | |
// if the element doesn't exist, abort | |
if( elem.length == 0 ) { | |
return; | |
} | |
var $window = jQuery(window) | |
var viewport_top = $window.scrollTop() | |
var viewport_height = $window.height() | |
var viewport_bottom = viewport_top + viewport_height | |
var $elem = jQuery(elem) | |
var top = $elem.offset().top | |
var height = $elem.height() | |
var bottom = top + height | |
return (top >= viewport_top && top < viewport_bottom) || | |
(bottom > viewport_top && bottom <= viewport_bottom) || | |
(height > viewport_height && top <= viewport_top && bottom >= viewport_bottom) | |
} | |
jQuery( document ).ready( function() { | |
window.addEventListener('scroll', function(e) { | |
if( isOnScreen( jQuery( '.shipping-logos' ) ) ) { /* Pass element id/class you want to check */ | |
alert( 'The specified container is in view.' ); | |
} | |
}); | |
}); |
Hello everyone,
is there a way to rewrite the code so that if the corresponding class appears more than once on the page, the code is executed again and not just the first time it appears?
Thank you.
Kind regards
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UPDATE:
I went back and updated
top
to include the website header and admin bar which appears when logged in(to WordPress).var top = $elem.offset().top + ($elem.height()/3 + $('#main-header').outerHeight() + $('#wpadminbar').outerHeight() )