Accedo a Google Drive desde Python

main.py

from google.oauth2.credentials import Credentials
from googleapiclient.discovery import build
from googleapiclient.errors import HttpError
from google.oauth2 import service_account


def get_service(api_name, api_version, scopes, key_file_location):
    """Get a service that communicates to a Google API.

    Args:
        api_name: The name of the api to connect to.
        api_version: The api version to connect to.
        scopes: A list auth scopes to authorize for the application.
        key_file_location: The path to a valid service account JSON key file.

    Returns:
        A service that is connected to the specified API.
    """

    credentials = service_account.Credentials.from_service_account_file(key_file_location)

    scoped_credentials = credentials.with_scopes(scopes)

    # Build the service object.
    service = build(api_name, api_version, credentials=scoped_credentials)

    return service


def main():
    """Shows basic usage of the Drive v3 API.
    Prints the names and ids of the first 10 files the user has access to.
    """

    # Define the auth scopes to request.
    scope = 'https://www.googleapis.com/auth/drive.metadata.readonly'
    key_file_location = 'credentials.json'

    try:
        # Authenticate and construct service.
        service = get_service(
            api_name='drive',
            api_version='v3',
            scopes=[scope],
            key_file_location=key_file_location)

        # Call the Drive v3 API
        results = service.files().list(
            pageSize=10, fields="nextPageToken, files(id, name)").execute()
        items = results.get('files', [])

        if not items:
            print('No files found.')
            return
        print('Files:')
        for item in items:
            print(u'{0} ({1})'.format(item['name'], item['id']))
    except HttpError as error:
        # TODO(developer) - Handle errors from drive API.
        print(f'An error occurred: {error}')


if __name__ == '__main__':
    main()