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Powershell - Brute force procedure
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$charset = @() | |
$charset += ([char]'0'..[char]'9') |% {[char]$_} | |
$charset += ([char]'a'..[char]'z') |% {[char]$_} | |
$charset += ([char]'A'..[char]'Z') |% {[char]$_} | |
$charset = $charset | Select-Object -uniq | |
function Get-NextPassword() { | |
param( | |
$Password | |
) | |
if (($Password -eq $null) -or ($Password -eq '')) { | |
#Started with nothing, return the first item of the character set. | |
return [string]$charset[0] | |
} | |
else { | |
for ($pass_pos = ($Password.Length - 1); $pass_pos -ge 0; $pass_pos--) { | |
$charset_pos = [array]::indexOf($charset, [char]$Password[$pass_pos]) | |
if ($charset_pos -eq $charset.Length - 1) { | |
#Overflow of the current password position. | |
$tempArray = $Password[0..$Password.Length] | |
$tempArray[$pass_pos] = $charset[0] | |
$Password = $tempArray -join "" | |
#Add character. Extend by 1 position. | |
if ($pass_pos -eq 0) { | |
$Password = $charset[0] + $Password | |
} | |
} | |
else { | |
#No overflow, update the current position +1 of the current character. | |
$tempArray = $Password[0..$Password.Length] | |
$tempArray[$pass_pos] = $charset[$charset_pos+1] | |
$Password = $tempArray -join "" | |
break #No overflow, therefore break the loop. | |
} | |
} | |
return $Password | |
} | |
} | |
$Password = $null | |
While ($true) { | |
$Password = Get-NextPassword $Password | |
$Password | |
} |
very nice code bru
bru nice code
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Nice. This will really help in penetration testing.