For @BillLaboon hey @FranklinChen is there an easy way in Haskell to find out which element in a list is most common, e.g. [1,1,1,2,3] -> 1 ?

ForBill.hs

import Test.HUnit

import qualified Data.List as List
import qualified Data.Ord as Ord
import Data.PSQueue as PSQueue

 {-
For @BillLaboon

hey @franklinchen is there an easy way in Haskell to find out which element in a list is most common, e.g. [1,1,1,2,3] -> 1 ?
-}
testMostCommon = TestCase $ mostCommon [1, 1, 1, 2, 3] @?= Just 1

-- Want a max priority queue with updateable priorities
mostCommon :: Ord a => [a] -> Maybe a
mostCommon xs =
  do
    k :-> _ <- PSQueue.findMin $ List.foldl' updateQueue PSQueue.empty xs
    return k

updateQueue :: (Num a, Ord k, Ord a) => PSQ k (Ord.Down a) -> k -> PSQ k (Ord.Down a)
updateQueue q key = PSQueue.alter updatePriority key q

updatePriority :: Num a => Maybe (Ord.Down a) -> Maybe (Ord.Down a)
updatePriority Nothing             = Just (Ord.Down 1)
updatePriority (Just (Ord.Down p)) = Just (Ord.Down (p+1))

I like how there are 7 lines of code, 4 lines of imports, 6 lines of comments, and 3 lines of (completely optional) type annotations. This is what my Haskell code typically looks like.

Oh, and I was lazy and had just 1 test case. In practice I would write some tests using QuickCheck to generate a couple hundred test cases automatically.

And the code is generic in key type (as long as can be ordered) and count type (as long as numeric and can be ordered).