Created
January 8, 2014 10:06
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Default values for hashes in ruby
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| # So... hash.new takes an optional parameter with a default value, that's neat. | |
| > hash = Hash.new(0) | |
| > hash["foo"] | |
| => 0 | |
| > hash["bar"] += 5 | |
| => 5 | |
| > hash | |
| => {"bar" => 5} | |
| # Cool, let's try something a bit more interesting | |
| > hash = Hash.new([]) | |
| > hash = Hash.new [] | |
| => {} | |
| > hash | |
| => {} | |
| > hash["foo"] | |
| => [] | |
| > hash["bar"] << 17 | |
| => [17] | |
| > hash | |
| => {} | |
| > hash["foo"] | |
| => [17] | |
| # Eh, what? That seems a bit odd. | |
| # It turns out that providing Hash.new with an array and then calling << for any non-existent value of that hash, actually modifies the default value. | |
| # That can be solved by providing a block to Hash.new, like so: | |
| > hash = Hash.new {|hsh, key| hsh[key] = [] } | |
| => {} | |
| > hash["foo"] | |
| => [] | |
| > hash | |
| => {"foo"=>[]} | |
| > hash["bar"] << 17 | |
| => [17] | |
| > hash | |
| => {"foo"=>[], "bar"=>[17]} | |
| # This, however, has the side-effect that even asking for a key will create it. | |
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