ES6 Currying Example

curryExample.js

function add (x, y) {return x+y}

let curry = (f, ...args) => f.bind.apply(f,[null, ...args])

let add4 = curry(add,4)
console.log(add4(5)) //9

let add4n6 = curry(add4,6)
console.log(add4n6()) //10

// try in babel
// https://babeljs.io/repl/#?evaluate=true&presets=es2015&experimental=false&loose=false&spec=false&code=function%20add%20(x%2C%20y)%20%7Breturn%20x%2By%7D%0A%0Alet%20curry%20%3D%20(f%2C%20...args)%20%3D%3E%20f.bind.apply(f%2C%5Bnull%2C%20...args%5D)%0A%0Alet%20add4%20%3D%20curry(add%2C4)%0Aconsole.log(add4(5))%20%2F%2F9%0A%0Alet%20add4n6%20%3D%20curry(add4%2C6)%0Aconsole.log(add4n6())%20%2F%2F10

This seems like partial application not curry.

With curry should you be able to do this:

var x = (a, b, c, d) => a + b + c + d; var y = curry(x)(1)(2)(3)(4);

Yeah, this isn't how curry works.

<script type="text/javascript"> "use strict"; var x = (a) => (b) => (c) => (d) => a + b + c + d; console.log( x(1)(2)(3)(4) ); </script>

At the console :

10