Created
January 11, 2011 19:44
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-module(utils). | |
-export([comball/1]). | |
-export([comball/2]). | |
-export([combuniq/1]). | |
%% Return all combinations of R elements in list L | |
comb([], _) -> [[]]; | |
comb(_, 0) -> [[]]; | |
comb(L, R) -> [[H|T] || H <- L, T <- comb(L -- [H], R-1)]. | |
%% Return all combinations of R, R-1, R-2... elements in list L | |
comball(L, R) -> | |
lists:flatmap(fun(X) -> comb(L, X) end, | |
lists:seq(1, R)). | |
%% Return all combinations of R, R-1, R-2... elements in list L, R=length(L) | |
comball(L) -> | |
comball(L, length(L)). | |
%% Return all unique combinations in order | |
combuniq(L) -> lists:sort(fun(X1,X2) -> | |
if length(X1)<length(X2) -> | |
true; | |
length(X1)>length(X2) -> | |
false; | |
true -> | |
X1 < X2 | |
end | |
end, lists:usort(lists:map(fun(R) -> lists:sort(R) end, | |
comball(L)))). |
Thanks! FP is like sculpting, you're happy when there's nothing left to remove :)
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Here's a slightly leaner version, based on a suggestion on twitter:
-module(test).
-export([allowed/1]).
% null case
allowed([]) ->
[];
% single element case
allowed([E]) ->
[[E]];
% allowed for H|T is H only, and all that is allowed for T,
% as well as that same set with H included.
allowed([H|T]) ->
L = allowed(T),
L ++ [[H]] ++ [[H | E] || E <- L].
FP is sometimes utterly frustrating. The easier it is to read, the longer it took to write :)