Applescript snippet to test if Option key is held down.

isOptionKeyPressed.scpt

on isOptionKeyPressed()
	return (do shell script "/usr/bin/python -c 'import Cocoa; print Cocoa.NSEvent.modifierFlags() & Cocoa.NSAlternateKeyMask > 1'") is "True"
end isOptionKeyPressed

what about this:

on getModKeys()
"/usr/bin/python -c 'import Cocoa;k="";a=Cocoa.NSEvent.modifierFlags()/65536
if a>31 : k=k+"function";a=a-32
if a>15 : k=k+"command";a=a-16
if a>7 : k=k+"option";a=a-8
if a>3 : k=k+"control";a=a-4
if a>1 :k=k+"shift";a=a-2
if a>0 :k=k+"capslock";print(k)'"
do shell script result
return result
end getModKeys

getModKeys()
if "shift" is in result then display dialog "shift key pressed"

Thanks @jimsmart !

Hi guys,

Thanks for your examples. I learned more about detecting key pressed.

@kennethrichardson's code works well. And he explained the founctionality of it. But I found key up, down, left and right will trigger the code. I modified a little bit to avoid this situation. I hope it is helpful for guys who face same case.

It works well in my Mac (Catalina 10.15.7).

Thanks.

on getModifierKeyBits()
	set modifierKeysDOWN to {command_down:false, option_down:false, control_down:false, shift_down:false, fn_down:false, capslock_down:false}
	set modifierBits to do shell script "/usr/bin/python -c 'import Cocoa; print Cocoa.NSEvent.modifierFlags()'"
	set modifierBits to modifierBits * 1
	if (modifierBits > 0) then
		if (modifierBits > 8388607) then
			if (modifierBits < 8388609) then
				-- fn key is pressed, subtract it away
				set modifierBits to modifierBits - 8388608
				set fn_down of modifierKeysDOWN to true
			end if
		end if
		if (modifierBits > 1048575) then
			if (modifierBits < 1048577) then
				-- command key is pressed, subtract it away
				set modifierBits to modifierBits - 1048576
				set command_down of modifierKeysDOWN to true
			end if
		end if
		if (modifierBits > 524287) then
			if (modifierBits < 524289) then
				-- option key is pressed, subtract it away
				set modifierBits to modifierBits - 524288
				set option_down of modifierKeysDOWN to true
			end if
		end if
		if (modifierBits > 262143) then
			if (modifierBits < 262145) then
				-- ctrl key is pressed, subtract it away
				set modifierBits to modifierBits - 262144
				set control_down of modifierKeysDOWN to true
			end if
		end if
		if (modifierBits > 131071) then
			if (modifierBits < 131073) then
				-- shift key is pressed, subtract it away
				set modifierBits to modifierBits - 131072
				set shift_down of modifierKeysDOWN to true
			end if
		end if
		if (modifierBits > 65535) then
			if (modifierBits < 65537) then
				-- capslock key is pressed, subtract it away
				set modifierBits to modifierBits - 65536
				set capslock_down of modifierKeysDOWN to true
			end if
		end if
	end if
	return modifierKeysDOWN
end getModifierKeyBits

I use very often lines that start with do shell script in my scripts. Unfortunately, the script won't compile if it contains the use framweork "Cocoa" line. Is there anything I can do about it? I've read that I need to use an NSTask object instead, but I can't figure out the mechanics of it.

This is the code that doesn't work.

use framework "Cocoa"
do shell script "eval $(/usr/libexec/path_helper -s); sendmidi dev SessionKiano ch 2 on 109 127"

Thank you.

EDIT:
I've found the solution:
According to this, I just needed to add below "use framework..." another line: use scripting additions.
Hurray!