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| import matplotlib.pyplot as plt | |
| import numpy as np | |
| from scipy.integrate import solve_ivp | |
| a, y0, g0 = 3, 100, 100 | |
| T = np.linspace(0, 30, 30) | |
| gs = [] | |
| for t in T: | |
| # G depends on Y | |
| def g_diff(t, g): | |
| # Y could be solved iteratively: | |
| # def y_diff(t, y): | |
| # return -y/a | |
| # solY = solve_ivp(y_diff, [0, t], [y0]) | |
| # y = solY.y[0][-1] | |
| # But it is just an exponential decay | |
| y = y0 * np.exp(-t/a) | |
| return y - min(50, g) | |
| # Solving G | |
| solG = solve_ivp(g_diff, [0, t], [g0]) | |
| gs.append(solG.y[0][-1]) | |
| # Plotting g & y | |
| plt.plot(T, gs, label='g') | |
| plt.legend() | |
| plt.show() |
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