Simple power made with types in TS

power.ts

// Multiplication comes from this issue:  https://github.com/type-challenges/type-challenges/issues/5814

type Reverse<A> =
  `${A}` extends `${infer AH}${infer AT}`
    ? `${Reverse<AT>}${AH}` : A

type Digs = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
type DigsNext<I = Digs, R = {}> =
  I extends [infer Head, infer Next, ...infer Tail]
    ? DigsNext<[Next, ...Tail], R & Record<Head, Next>>
    : { [K in keyof R]: R[K] }
type DigsPrev = { [K in keyof DigsNext as DigsNext[K]]: K }

type AddOne<A> =
  A extends `${infer AH}${infer AT}`
    ? AH extends '9' ? `0${AddOne<AT>}` : `${DigsNext[AH]}${AT}`
    : `1`

type SubOne<A> =
  A extends `${infer AH}${infer AT}`
    ? AH extends '0' ? `9${SubOne<AT>}` : `${DigsPrev[AH]}${AT}`
    : never

type Add<A, B> =
  A extends `${infer AH}${infer AT}` ?
    B extends `${infer BH}${infer BT}`
      ? BH extends '0' ? `${AH}${Add<AT, BT>}` : Add<AddOne<A>, SubOne<B>>
      : A : B

type Mul<A, B, R = '0'> =
  A extends '0' ? R :
    B extends '0' ? R :
      A extends `${infer AH}${infer AT}`
        ? AH extends '0' ? Mul<AT, `0${B}`, R> : Mul<SubOne<A>, B, Add<R, B>>
        : R

type Multiply<A extends string | number | bigint, B extends string | number | bigint> =
  Reverse<Mul<Reverse<A>, Reverse<B>>>

type Power<
  V extends string,
  P extends string,
  A extends string = V> =
  P extends '1'
    ? A
    : P extends '0'
      ? '1'
      : Power<V, SubOne<P>, Multiply<V, A>>

const $: Power<'2', '4'> = "16";
const _: Power<'2', '3'> = "8";