Created
February 27, 2021 01:21
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#include <iostream> | |
#include <vector> | |
#include <thread> | |
#include <chrono> | |
#include <algorithm> | |
using namespace std; | |
using namespace std::chrono; | |
int SIZE = 10; | |
void indexSort(int arr[], int n) { | |
int index[n]; | |
for (int i = 0; i < n; ++i) index[i] = i; | |
for(int i=0;i < n;i++) { | |
for(int j=i+1;j < n;j++) { | |
if(arr[index[i]] > arr[index[j]]) { | |
int temp = index[i]; | |
index[i] = index[j]; | |
index[j] = temp; | |
} | |
} | |
} | |
vector<int> v; | |
for (int i = 0; i < n; ++i) { | |
v.push_back(arr[index[i]]); | |
} | |
for (int i = 0; i < n; ++i) arr[i] = v[i]; | |
} | |
void printArray(vector<int>& array); | |
void printArray(int *array, int sz); | |
void mergeArrays(int arr1[], int arr2[], int n1, | |
int n2, int arr3[]); | |
int main() { | |
vector<int> a(SIZE); | |
int* leftArray = (int *)malloc((SIZE/2+1) * sizeof(int)); | |
int* rightArray = (int *)malloc((SIZE/2+1) * sizeof(int)); | |
for (int m = 0; m < SIZE; m++) { | |
a[m] = rand()%10; | |
} | |
for (int i = 0; i < SIZE/2; ++i) leftArray[i] = a[i]; | |
for (int i = 0, j = SIZE/2; i < SIZE/2; ++i, j++) { | |
rightArray[i] = a[j]; | |
} | |
thread t1 (indexSort, leftArray, SIZE/2); | |
thread t2 (indexSort, rightArray, SIZE/2); | |
t1.join(); | |
t2.join(); | |
int sortedArray[SIZE]; | |
mergeArrays(leftArray, rightArray, SIZE/2, SIZE/2, sortedArray); | |
// printArray(leftArray, SIZE/2); | |
// printArray(rightArray, SIZE/2); | |
printArray(a); | |
printArray(sortedArray, SIZE); | |
cout << endl; | |
return 0; | |
} | |
void printArray(vector<int>& array){ | |
for (int i = 0; i < SIZE; ++i) cout << array[i] << ' '; | |
cout << endl; | |
} | |
void printArray(int *array, int sz){ | |
for (int i = 0; i < sz; ++i) cout << array[i] << ' '; | |
cout << endl; | |
} | |
void mergeArrays(int arr1[], int arr2[], int n1, | |
int n2, int arr3[]) { | |
int i = 0, j = 0, k = 0; | |
while (i<n1 && j <n2) { | |
if (arr1[i] < arr2[j]) | |
arr3[k++] = arr1[i++]; | |
else | |
arr3[k++] = arr2[j++]; | |
} | |
while (i < n1) | |
arr3[k++] = arr1[i++]; | |
while (j < n2) | |
arr3[k++] = arr2[j++]; | |
} |
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