CalculatingDartThrown.py

import prompt
import predicate
import random

DartThrown = prompt.for_int('Enter number of darts to throw', is_legal= predicate.is_positive)
count = 0

for i in range(DartThrown): 
    #print('Dart Thrown')
    x = random.uniform(-1, 1) 
    y = random.uniform(-1, 1)
    #print('    x=', x,'/', 'y=', y)
    if x**2+y**2 <= 1:
        #print('    Inside Circle')
        count += 1
        #print('    Inside Count', count)
        #print('    Outside Circle')
        #print('    Inside Count=', count)

pi_approximate = (count/DartThrown)*4
print('pi is approximately =', pi_approximate)