计算1-9不重复填入九宫格,横竖斜相加和相等

calc.py

count = 0
for i in range(1, 10):
    for j in range(1, 10):
        a = [i, j, 15-i-j]
        if len(set(a)) < 3 or 15-i-j<1:
            count += 1
            continue

        for k in range(1, 10):
            for l in range(1, 10):
                b = [k, l, 15-k-l]
                if len(set(b)) < 3 or 15-k-l<1:
                    count += 1
                    
                    continue

                for m in range(1, 10):
                    for n in range(1, 10):
                        c = [m, n, 15-m-n]
                        if len(set(c)) < 3 or 15-m-n<1:
                            count += 1
                            continue
                        count += 1

#                        if a[0]+b[0]+c[0] ==15 and a[1]+b[1]+c[1]==15 and a[2]+b[2]+c[2]==15 and len(set(a) & set(b))+ len(set(a) & set(c)) + len(set(b) & set(c)) == 0:
                        if a[0]+b[0]+c[0] ==15 and a[1]+b[1]+c[1]==15 and a[2]+b[2]+c[2]==15 and len(set(a) & set(b))+ len(set(a) & set(c)) + len(set(b) & set(c)) == 0\
                         and a[0]+b[1]+c[2]==15 and a[2]+b[1]+c[0]==15:
                            print("*"*15)
                            print(a)
                            print(b)
                            print(c)

print(count)

O----O----O
|    |    |
O----O----O
|    |    |
O----O----O

依次填入1-9的数使得横竖相加和为15