Find Numbers with Even Number of Digits

main.md

Question

Approach

To solve this, I just iterated through the nums array and for each number, I counted the number of digits using either len(str(num)) or logarithmic math. If the number of digits was even, I incremented a counter.

Implementation

class Solution:
    def findNumbers(self, nums: List[int]) -> int:
        count = 0
        for num in nums:
            if len(str(num)) % 2 == 0:
                count += 1
        return count

Complexities

• Time: O(n)
• Space: O(1)