Build Array from Permutation

main.md

Question

Approach

I used a simple list comprehension to construct the result array in a clean and efficient way.

Implementation

class Solution:
    def buildArray(self, nums: List[int]) -> List[int]:
        return [nums[nums[i]] for i in range(len(nums))]

Complexities

• Time: O(n)
• Space: O(n)