Calculate Poker side pots using this NodeJS script written in javascript ES6.

sidepots.js

#!/usr/bin/env node
let players = process.argv.slice(2)

if (players.length < 2) return console.log('There has to be at least two players to calculate side-pots.')

players = players
  // give each player a name
  .map((p, i) => ({name: `Player ${i + 1}`, bet: p}))

  // sort from lowest to highest
  .sort((a, b) => a.bet - b.bet)

// distribute side pots
const sidePots = []

players.forEach(({name, bet}, currentPlayerIndex) => {
  // no side pot for the first player that goes all-in
  if (currentPlayerIndex === 0) return

  // the last player to go all-in doesn't create a side pot
  for (let i = currentPlayerIndex - 1;i > 1;i--){
    bet -= players[i].bet - players[i - 1].bet
  }

  // everyone bets in the main pot
  bet -= players[0].bet

  // add current player to all existing sidepots
  sidePots.forEach(({players}) => players.push(name))

  // the side pot is equal to the amount of players in the pot * the minimum bet
  let sidePot = {pot: (players.length - currentPlayerIndex) * bet, players: [name]}

  // do not push empty sidepot
  sidePot.pot && sidePots.push(sidePot)
})

// if a player is alone in a side pot he can take back his money right away
let potOver
const lastSidePot = sidePots.slice(-1)[0]
if (lastSidePot.players && lastSidePot.players.length === 1) potOver = sidePots.pop()

// OUTPUT
potOver && console.log(`${potOver.players[0]} takes back ${potOver.pot}$`)

console.log(`Main pot: ${players.length * players[0].bet}$ - All players`)

sidePots.forEach(({pot, players}, i) => {
  console.log(`Side pot ${i + 1}: ${pot}$ - ${players.sort()}`)
})

what happens if someone has raised and first player that has bet folded... you can not calculate pot amount simply just by multiplying first bet with player count