Paranthese counting

pars.c

#include <stdio.h>
#include <string.h>

/**
 * @author: Jan P. B.
 * Purpose: Count parentheses in a string.
 * Used to count capture groups for SLRE - and as string practice for Jan. :)
 * 
 * @param {char*} c   : Buffer
 * @param {int}   len : Buffer length
 * @return {int} Number of parenthesis, -1 on error.
 * 
 * @NOTE: Might want to comment out the printf()s, or throw some kind of exception...
 */
int countbrackets(char* c, int len) {
    char prevchar=' ';
    int braop=0;
    int bracl=0;

    for(int i=0; i<len; i++) {
        if (c[i]=='(' && prevchar!='\\') {
            braop++;
        } else if (c[i]==')' && prevchar!='\\') {
            bracl++;
        }
        prevchar = c[i];
    }

    if (braop==bracl) {
        return braop;
    } else {
        if (braop>bracl)
            printf("es gibt mehr ( wie )");
        else {
            printf("es gibt mehr ) wie (");
            return -1;
        }
    }
    // Silencing "Function reaching end of control"
    return -1;
}

int main() {
    char* pattern = "(\\d).(\\d).(\\d) \\((.+)\\)\0";
    int len = strlen(pattern);
    int pars = countbrackets(pattern, len);
    printf(
        "String: %s\nLen: %i\nPars:%i\n",
        pattern, len, pars
    );
}

/*
Expecting:
(\d).(\d).(\d) \((.+)\)
^^^^ ^^^^ ^^^^   ^^^^ = 4
Output:
[email protected]_W723_V_Typ_A_1_01_012 /tmp $ gcc pars.c -o pars; and ./pars
String: (\d).(\d).(\d) \((.+)\)
Len: 23
Pars:4
*/