The Shaggy Problem in Python !

Shaggy.py

```

'''
This is a game where you must count to number from 0 to 1000. However, if the number has a 6 in it, or is divisible by 6, you don't say the number. Instead, you say "Shaggy".

Rules:

You can't hard-code the numbers.
The number only has to satisfy at least 1 of the following requirements
Divisible by 6
Number contains a 6
Some type of separator is mandatory (12345Shaggy7.. doesn't count)
You must count exactly to 1000 from 1.
The numbers must be output, but it doesn't matter how (e.g., stdout, writing to a text file, etc.).
'''
def is_true(i):
    i=str(i)
    if '6' in i:
        return True
    return False


def is_digitPresent(n):
    for i in range (n):
        if i%6==0 or is_true(i):
            print("shaggy!")
        else :
            print(i)



if __name__ == '__main__':
    n=int(input())
    is_digitPresent(n)


```