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K strongest Values in an Array
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''' | |
Given an array of integers arr and an integer k. | |
A value arr[i] is said to be stronger than a value arr[j] if |arr[i] - m| > |arr[j] - m| | |
where m is the median of the array. | |
If |arr[i] - m| == |arr[j] - m|, then arr[i] is said to be stronger than arr[j] if arr[i] > arr[j]. | |
Return a list of the strongest k values in the array. return the answer in any arbitrary order. | |
Median is the middle value in an ordered integer list. More formally, if the length of the list is n, | |
the median is the element in position ((n - 1) / 2) in the sorted list (0-indexed). | |
For arr = [6, -3, 7, 2, 11], n = 5 and the median is obtained by sorting the array arr = [-3, 2, 6, 7, 11] | |
and the median is arr[m] where m = ((5 - 1) / 2) = 2. The median is 6. | |
For arr = [-7, 22, 17, 3], n = 4 and the median is obtained by sorting the array arr = [-7, 3, 17, 22] | |
and the median is arr[m] where m = ((4 - 1) / 2) = 1. The median is 3. | |
Example 1: | |
Input: arr = [1,2,3,4,5], k = 2 | |
Output: [5,1] | |
Explanation: Median is 3, the elements of the array sorted by the strongest are [5,1,4,2,3]. | |
The strongest 2 elements are [5, 1]. [1, 5] is also accepted answer. | |
Please note that although |5 - 3| == |1 - 3| but 5 is stronger than 1 because 5 > 1. | |
Example 2: | |
Input: arr = [1,1,3,5,5], k = 2 | |
Output: [5,5] | |
Explanation: Median is 3, the elements of the array sorted by the strongest are [5,5,1,1,3]. | |
The strongest 2 elements are [5, 5]. | |
''' | |
class Solution: | |
def getStrongest(self, arr: List[int], k: int) -> List[int]: | |
if not arr: | |
return 0 | |
a=b=0 | |
arr.sort() | |
n=len(arr) | |
med=arr[(n-1)//2] | |
i,j=0,len(arr)-1 | |
result=[] | |
while k>0: | |
a=abs(arr[i]-med) | |
b=abs(arr[j]-med) | |
if a>b or (a==b and arr[i]>arr[j]): | |
result.append(arr[i]) | |
i+=1 | |
else : | |
result.append(arr[j]) | |
j-=1 | |
k-=1 | |
return result | |
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